-16t^2+31t+2=Y

Solution for -16t^2+31t+2=Y equation:

-16t^2+31t+2=

We move all terms to the left:

-16t^2+31t+2-()=0

We add all the numbers together, and all the variables

-16t^2+31t=0

a = -16; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·(-16)·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*-16}=\frac{-62}{-32}
=1+15/16
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*-16}=\frac{0}{-32}
=0
$